JS Practice — Built-in Objects

Function.prototype.call() — Math.max with call()

📖 Usage Example

const obj = { val: 5 }
function double() { return this.val * 2 }
double.call(obj)  // → 10

call() is identical to apply() except arguments are passed individually.

Using call() with Math.max

Math.max expects individual arguments. You can invoke it with call() passing null as this.

Challenge: Use Math.max.call(null, 1, 2, 3) and verify the result is 3.

💡 Hints (1)