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Mathacoshintermediate

Math.acosh(2) β‰ˆ 1.317

πŸ“– Usage Example
// Inverse hyperbolic cosine (input must be β‰₯ 1)
Math.acosh(1)   // β†’ 0
Math.acosh(2)   // β†’ 1.3169...

Use Math.acosh() to compute the inverse hyperbolic cosine of a number β‰₯ 1.

Math.acosh(x)

Math.acosh(2) returns approximately 1.3170.

Challenge: Compute and verify Math.acosh(2).

πŸ’‘ Hints (2)
  • β€’ acosh(x) = ln(x + √(xΒ²βˆ’1))
  • β€’ Valid for all x β‰₯ 1