expm1beginner// e^x minus 1, precise for very small x
Math.expm1(0) // β 0
Math.expm1(0.001) // β 0.0010005...Use Math.expm1(x) instead of Math.exp(x) - 1 for small x values to avoid floating-point precision loss.
Returns eΛ£ - 1 with higher precision for small values of x. Math.expm1(0) returns 0.
Challenge: Use Math.expm1() and verify its result for input 0.