JS Practice — Built-in Objects

Math.expm1(1) ≈ e - 1 ≈ 1.718

📖 Usage Example

// e^x minus 1, precise for very small x
Math.expm1(0)     // → 0
Math.expm1(0.001) // → 0.0010005...

Use Math.expm1(x) instead of Math.exp(x) - 1 for small x values to avoid floating-point precision loss.

Math.expm1(x)

Math.expm1(1) returns Math.E - 1 (approximately 1.7183).

Challenge: Verify that Math.expm1(1) equals Math.E - 1.

💡 Hints (2)